# How To Count Fish

We have a pond out back, and in 2013, added some goldfish to it. The goldfish, finding themselves in a comfortable spot with clean water, went about the business of making more goldfish. They didn’t have much time to do that before winter of 2013, but they had a very good summer in 2014, producing so many baby goldfish that we got a bit tired of discovering new babies. The pond isn’t quite deep enough that we could be sure it was safe for them to winter over, so we had to work out moving them to a tub indoors. This required, among other things, having an idea how many goldfish there were. The question then was: how many goldfish were in the pond?

It’s not hard to come up with a maximum estimate: a goldfish needs some amount of water to be healthy. Wikipedia seems to suggest a single fish needs about twenty gallons — call it 80 liters — and I’ll accept that since it sounds plausible enough and it doesn’t change the logic of the maximum estimate if the number is actually something different. The pond’s about ten feet across, and roughly circular, and not quite two feet deep. Call that a circular cylinder, with a diameter of three meters, and a depth of two-thirds of a meter, and that implies a volume of about pi times (3/2) squared times (2/3) cubic meters. That’s about 4.7 cubic meters, or 4700 liters. So there probably would be at most 60 goldfish in the pond. Could the goldfish have reached the pond’s maximum carrying capacity that quickly? Easily; you would not believe how fast goldfish will make more goldfish given fresh water and a little warm weather.

It can be a little harder to quite believe in the maximum estimate. For one, smaller fish don’t need as much water as bigger ones do and the baby fish are, after all, small. Or, since we don’t really know how deep the pond is — it’s not a very regular bottom, and it’s covered with water — might there be even more water and thus capacity for even more fish? That might sound ridiculous but consider: an error of two inches in my estimate of the pond’s depth amounts to a difference of 350 liters or room for four or five fish.

We can turn to probability, though. If we have some way of catching fish — and we have; we’ve got a wire trap and a mesh trap, which we’d use for bringing in fish — we could set them out and see how many fish we can catch. If we suppose there’s a certain probability $p$ of catching any one fish, and if there are $N$ fish in the pond any of which might be caught, then we could expect that some number $M = N \cdot p$ fish are going to be caught. So if, say, we have a one-in-three chance of catching a fish, and after trying we’ve got some number $M$ fish — let’s say there were 8 caught, so we have some specific number to play with — we could conclude that there must have been about $M \div p = 8 \div \frac{1}{3}$ or 24 fish in the population to catch.

This does bring up the problem of how to guess what the probability of catching any one fish is. But if we make some reasonable-sounding assumptions we can get an estimate of that: set out the traps and catch some number, call it $n$, of fish. Then set them back and after they’ve had time to recover from the experience, put the traps out again to catch $n$ fish again. We can expect that of that bunch there will be some number, call it $m$, of the fish we’d previously caught. The ratio of the fish we catch twice to the number of fish we caught in the first place should be close to the chance of catching any one fish.

So let’s lay all this out. If there are some unknown number $N$ fish in the pond, and there is a chance of $\frac{m}{n}$ of any one fish being caught, and we’ve caught in seriously trying $M$ fish, then: $M = N \cdot \frac{m}{n}$ and therefore $N = M \cdot \frac{n}{m}$.

For example, suppose in practice we caught ten fish, and were able to re-catch four of them. Then in trying seriously we caught twelve fish. From this we’d conclude that $n = 10, m = 4, M = 12$ and therefore there are about $N = M \cdot \frac{m}{n} = 12 \cdot \frac{10}{4} = 30$ fish in the pond.

Or if in practice we’d caught twelve fish, five of them a second time, and then in trying seriously we caught eleven fish. Then since $n = 12, m = 5, M = 11$ we get an estimate of $N = M \cdot \frac{m}{n} = 11 \cdot \frac{12}{5} = 26.4$ or call it 26 fish in the pond.

Or for another variation: suppose the first time out we caught nine fish, and the second time around, catching another nine, we re-caught three of them. If we’re feeling a little lazy we can skip going around and catching fish again, and just use the figures that $n = 9, m = 3, M = 9$ and from that conclude there are about $N = 9 \cdot \frac{9}{3} = 27$ fish in the pond.

So, in principle, if we’ve made assumptions about the fish population that are right, or at least close enough to right, we can estimate what the fish population is without having to go to the work of catching every single one of them.

Since this is a generally useful scheme for estimating a population let me lay it out in an easy-to-follow formula.

To estimate the size of a population of $N$ things, assuming that they are all equally likely to be detected by some system (being caught in a trap, being photographed by someone at a spot, anything), try this:

1. Catch some particular number $n$ of the things. Then let them go back about their business.
2. Catch another $n$ of them. Count the number $m$ of them that you caught before.
3. The chance of catching one is therefore about $p = m \div n$.
4. Catch some number $M$ of the things.
5. Since — we assume — every one of the $N$ things had the same chance $p$ of being caught, and since we caught $M$ of them, then we estimate there to be $N = M \div p$ of the things to catch.

Warning! There is a world of trouble hidden in that “we assume” on the last step there. Do not use this for professional wildlife-population-estimation until you have fully understood those two words.

## Author: Joseph Nebus

I was born 198 years to the day after Johnny Appleseed. The differences between us do not end there. He/him.

## 9 thoughts on “How To Count Fish”

1. The pond’s gotten iced over, so we’ve caught all the fish we’ll be getting for this winter. We know there are some left in yet, but I did spot at least one of them alive and apparently well recently. And it hasn’t been as hard a winter as last year’s was, so, we’re hopeful. In another month we could reasonably expect the weather to spend most of its time above freezing and then we can get to the problem of moving the fish back out.

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1. I wonder if you could measure a charactistic amount of something that fish extract from the water or they produce? Such as: Oxygen content, or food not yet eaten after X hours, or their sh*t?
Or fish need to mutate so that they will emit light at a specific wavelength and intensity. In any case, you could measure the number of fish by measuring the grand total of some stuff.

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1. It’s very tempting to think of counting the fish by measuring biological processes in the pond. But the pond and the population are probably at just the wrong scale for that to be useful: there’s fish that are barely two finger-widths long, while some of the adults are maybe one and a half times my hand’s greatest extent. With that kind of distribution of body size, anything that tries measuring, like, oxygen use or food consumption is just going to be swamped by the error margins.

If the pond were smaller, so none of the fish ever got that huge (goldfish size is limited by water quality, which depends on, well, fish size and number, among other factors) then we could work out an average fish metabolism and believe in the numbers. If the pond were larger, so that the fish population would be in the tens of thousands, we could use an average fish metabolism and trust in the Law of Large Numbers that the really huge and really small fish are going to balance one another out.

As it is, I don’t believe the pond or the population is big enough that we can rely on averages like that, and it’s not small enough to make fish-tracking easy. It’s very nice to look at on a warm day, though.

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